1. **State the problem:** We need to evaluate the integral $$\int 202x^2 - 4 \, dx$$. 2. **Recall the integral rules:** The integral of a sum is the sum of the integrals, and the integral of $$x^n$$ is $$\frac{x^{n+1}}{n+1}$$ plus a constant. 3. **Apply the integral to each term:** $$\int 202x^2 \, dx = 202 \int x^2 \, dx = 202 \cdot \frac{x^{3}}{3} = \frac{202}{3} x^3$$ $$\int -4 \, dx = -4x$$ 4. **Combine the results and add the constant of integration:** $$\int 202x^2 - 4 \, dx = \frac{202}{3} x^3 - 4x + C$$ 5. **Final answer:** $$\boxed{\frac{202}{3} x^3 - 4x + C}$$