1. **State the problem:** Find the indefinite integral $$\int (x+1) \, dx$$.
2. **Recall the integral rule:** The integral of a sum is the sum of the integrals, so
$$\int (x+1) \, dx = \int x \, dx + \int 1 \, dx$$.
3. **Integrate each term:**
- The integral of $$x$$ is $$\frac{x^2}{2}$$.
- The integral of $$1$$ is $$x$$.
4. **Combine results and add the constant of integration:**
$$\int (x+1) \, dx = \frac{x^2}{2} + x + C$$, where $$C$$ is an arbitrary constant.
**Final answer:** $$\boxed{\frac{x^2}{2} + x + C}$$
Integral X Plus One Ac2Fc8
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