1. The problem is to find the integral of the function $y^{-2}$ with respect to $y$.
2. Recall the power rule for integration: $$\int y^n \, dy = \frac{y^{n+1}}{n+1} + C \quad \text{for } n \neq -1.$$ Here, $n = -2$.
3. Applying the power rule:
$$\int y^{-2} \, dy = \frac{y^{-2+1}}{-2+1} + C = \frac{y^{-1}}{-1} + C = -y^{-1} + C.$$
4. Simplify the expression:
$$-y^{-1} + C = -\frac{1}{y} + C.$$
5. Therefore, the integral of $y^{-2}$ is:
$$\boxed{-\frac{1}{y} + C}.$$
Integral Y^ 2 C92F96
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.