1. **State the problem:** We are given the derivative $$y' = \frac{1}{\sqrt{3 - x^2}}$$ and asked to find the general solution for $$y$$. 2. **Recall the formula and rules:** To find $$y$$, we integrate $$y'$$ with respect to $$x$$: $$y = \int y' \, dx = \int \frac{1}{\sqrt{3 - x^2}} \, dx$$ 3. **Integration technique:** The integral $$\int \frac{1}{\sqrt{a^2 - x^2}} \, dx = \arcsin\left(\frac{x}{a}\right) + C$$ where $$a > 0$$. 4. **Apply the formula:** Here, $$a = \sqrt{3}$$, so $$y = \arcsin\left(\frac{x}{\sqrt{3}}\right) + C$$ 5. **Rewrite the solution:** The problem states the solution as $$y = B \sin\left(\frac{x}{\sqrt{3}}\right) + C$$, but this is not the integral of $$y'$$. The correct integral is the arcsine function, not sine. 6. **Final answer:** $$y = \arcsin\left(\frac{x}{\sqrt{3}}\right) + C$$ where $$C \in \mathbb{R}$$. This is the general solution to the differential equation given.