1. We are asked to find the limit $\lim_{x \to 1} f(4-2x)$.\n\n2. The limit expression is $\lim_{x \to 1} f(4-2x)$. To evaluate this, we substitute $x=1$ into the inner function: $4 - 2(1) = 4 - 2 = 2$.\n\n3. Therefore, $\lim_{x \to 1} f(4-2x) = f(2)$.\n\nSince the problem does not provide the explicit form of $f$, the limit is expressed in terms of $f(2)$.\n