1. The problem asks to find the limit: $$\lim_{x \to 0} \frac{1}{x^2}$$. 2. Recall that $x^2$ is the square of $x$, so it is always positive except at $x=0$ where it is zero. 3. As $x$ approaches 0, $x^2$ approaches 0 from the positive side, so the denominator becomes very small. 4. The expression $\frac{1}{x^2}$ means 1 divided by a very small positive number, which grows without bound. 5. Therefore, $$\lim_{x \to 0} \frac{1}{x^2} = +\infty$$, which means the limit tends to infinity. 6. In plain language, as $x$ gets closer and closer to zero, $\frac{1}{x^2}$ becomes larger and larger without limit. Final answer: $$\lim_{x \to 0} \frac{1}{x^2} = +\infty$$.