Subjects calculus

Limit Linear 219B16

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1. The problem asks to find the limit \(\lim_{x \to 1} 4x - 3\) using a graph. 2. The function is \(y = 4x - 3\), which is a linear function with slope 4 and y-intercept -3. 3. To sketch the graph: - Plot the y-intercept at \( (0, -3) \). - Use the slope 4 to find another point: from \(x=0\) to \(x=1\), y increases by 4, so point \( (1, 1) \). 4. The graph is a straight line passing through points \((0, -3)\) and \((1, 1)\). 5. To find the limit as \(x\) approaches 1, evaluate the function at \(x=1\): $$4(1) - 3 = 4 - 3 = 1$$ 6. Therefore, \(\lim_{x \to 1} 4x - 3 = 1\). Final answer: 1