1. **Problem:** Evaluate the limit $$\lim_{t \to 0} \frac{\sin t}{t}$$ using special limits.
2. **Formula and important rule:** The special limit $$\lim_{x \to 0} \frac{\sin x}{x} = 1$$ is fundamental in calculus.
3. **Step-by-step solution:**
1. Recognize that the limit matches the special limit form directly.
2. Therefore, $$\lim_{t \to 0} \frac{\sin t}{t} = 1$$.
4. **Explanation:** This limit is a standard result that helps evaluate many trigonometric limits. It states that as the angle approaches zero, the ratio of sine of the angle to the angle itself approaches 1.
**Final answer:** $$1$$
Limit Sin Over T C6B064
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