1. **State the problem:** Find the limit as $x$ approaches 0 of the expression $$\frac{x^2 - x}{\sqrt{3} - \sqrt{3} - x}.$$ 2. **Simplify the denominator:** Notice that $\sqrt{3} - \sqrt{3} = 0$, so the expression simplifies to $$\frac{x^2 - x}{-x}.$$ 3. **Factor the numerator:** Factor $x$ out of the numerator: $$\frac{x(x - 1)}{-x}.$$ 4. **Cancel common factors:** Since $x \neq 0$ (we are taking a limit as $x \to 0$, not at $x=0$), we can cancel $x$ in numerator and denominator: $$\frac{\cancel{x}(x - 1)}{-\cancel{x}} = \frac{x - 1}{-1}.$$ 5. **Simplify the expression:** $$\frac{x - 1}{-1} = -x + 1.$$ 6. **Evaluate the limit:** Substitute $x = 0$ into the simplified expression: $$-0 + 1 = 1.$$ **Final answer:** $$\lim_{x \to 0} \frac{x^2 - x}{\sqrt{3} - \sqrt{3} - x} = 1.$$