1. The problem asks about the meaning of the statement: "Odd function over symmetric limit is zero." 2. An odd function $f(x)$ satisfies the property $f(-x) = -f(x)$ for all $x$ in its domain. 3. When integrating an odd function over a symmetric interval $[-a, a]$, the integral is zero because the areas on the negative and positive sides cancel each other out. 4. Mathematically, this is expressed as $$\int_{-a}^a f(x) \, dx = 0$$ if $f$ is odd. 5. This happens because the integral from $-a$ to $0$ is the negative of the integral from $0$ to $a$, so they sum to zero. 6. Therefore, the statement means that the definite integral of an odd function over an interval symmetric about zero equals zero.