1. The problem is to understand and use partial derivatives.
2. Partial derivatives measure how a multivariable function changes as one variable changes, keeping others constant.
3. For a function $f(x,y)$, the partial derivative with respect to $x$ is denoted $\frac{\partial f}{\partial x}$ and with respect to $y$ is $\frac{\partial f}{\partial y}$.
4. To compute $\frac{\partial f}{\partial x}$, treat $y$ as a constant and differentiate $f$ with respect to $x$.
5. Similarly, to compute $\frac{\partial f}{\partial y}$, treat $x$ as a constant and differentiate $f$ with respect to $y$.
6. Example: Given $f(x,y) = x^2 y + 3xy^2$, find $\frac{\partial f}{\partial x}$ and $\frac{\partial f}{\partial y}$.
7. Compute $\frac{\partial f}{\partial x}$:
$$\frac{\partial}{\partial x}(x^2 y + 3xy^2) = 2x y + 3 y^2$$
8. Compute $\frac{\partial f}{\partial y}$:
$$\frac{\partial}{\partial y}(x^2 y + 3xy^2) = x^2 + 6 x y$$
9. These partial derivatives tell us how $f$ changes as $x$ or $y$ changes independently.
Final answer:
$$\frac{\partial f}{\partial x} = 2 x y + 3 y^2$$
$$\frac{\partial f}{\partial y} = x^2 + 6 x y$$
Partial Derivatives 8C7454
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