1. The problem asks to find the right-hand limit of the function $f(x)$ as $x$ approaches 0, denoted as $\lim_{x \to 0^+} f(x)$. 2. The right-hand limit means we look at values of $f(x)$ as $x$ approaches 0 from values greater than 0. 3. From the graph description, at $x=0$ there is a jump discontinuity: an open circle at $(0,0)$ and a solid dot at $(0,1)$. 4. The solid dot at $(0,1)$ represents the value of $f(0)$, but the limit from the right depends on the values of $f(x)$ for $x>0$ close to 0. 5. The graph segment to the right of 0 rises from just above 0 to 1 at $x=0$, so as $x \to 0^+$, $f(x)$ approaches 1. 6. Therefore, the right-hand limit is $$\lim_{x \to 0^+} f(x) = 1.$$