1. Let's analyze the expression you provided: $$-\cos x \sin^2 x + \cos x \ln(\cos x)$$ and compare it to $$-\cos x \sin^2 x - \cos x \ln(\cos x)$$. 2. The difference lies in the sign before the term $\cos x \ln(\cos x)$. 3. To understand why the first expression has a plus sign, consider the original derivation or context where this expression came from. Often, signs depend on operations like differentiation, integration, or algebraic manipulation. 4. For example, if this expression is from differentiating a product or applying the chain rule, the sign comes from the derivative rules. 5. Without the original problem context, the key is to carefully track signs during each step of your calculation. 6. If you made a sign error, it might be due to misapplying the negative sign or forgetting to distribute it across terms. 7. Always write intermediate steps explicitly and check the sign of each term. 8. If you want, provide the original problem or steps, and I can help identify exactly where the sign changes. In summary, the expression $$-\cos x \sin^2 x + \cos x \ln(\cos x)$$ is correct if the derivation leads to a positive sign before $\cos x \ln(\cos x)$, otherwise it should be negative. The sign depends on the operations performed before arriving at this expression.