Subjects calculus

Sin Z Integral

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1. The problem is to evaluate the integral $$\int \frac{\sin z}{(z+\Pi)x^3} \, dz$$ where the variable of integration is $z$ and $x$ is treated as a constant. 2. Since $x$ is constant with respect to $z$, we can factor out $\frac{1}{x^3}$: $$\int \frac{\sin z}{(z+\Pi)x^3} \, dz = \frac{1}{x^3} \int \frac{\sin z}{z+\Pi} \, dz$$ 3. The integral $$\int \frac{\sin z}{z+\Pi} \, dz$$ does not have a simple elementary antiderivative. It is a non-elementary integral often expressed in terms of special functions or evaluated numerically. 4. Therefore, the integral can be expressed as: $$\frac{1}{x^3} \int \frac{\sin z}{z+\Pi} \, dz + C$$ where $C$ is the constant of integration. 5. In summary, the integral cannot be simplified further using elementary functions, and the factor $\frac{1}{x^3}$ is constant with respect to $z$. Final answer: $$\int \frac{\sin z}{(z+\Pi)x^3} \, dz = \frac{1}{x^3} \int \frac{\sin z}{z+\Pi} \, dz + C$$