1. The problem asks which slope field corresponds to the function $y = e^x$. 2. Recall that the slope field for a differential equation $\frac{dy}{dx} = f(x,y)$ shows small line segments with slope $f(x,y)$ at each point $(x,y)$. 3. For $y = e^x$, the derivative is $\frac{dy}{dx} = e^x$. This means the slope at any point depends only on $x$ and is always positive, increasing as $x$ increases. 4. Therefore, the slope field for $y = e^x$ should have slopes that are: - Small (close to 0) when $x$ is very negative, - Increasing as $x$ moves to the right, - Independent of $y$ (the slope does not change vertically). 5. Among the described graphs: - Graph 1 shows slopes increasing with $x$ and changing gradually with $y$, which is inconsistent because slope should not depend on $y$. - Graph 2 shows nearly horizontal slopes for negative $x$ and increasing steepness for positive $x$, independent of $y$, matching the behavior of $y = e^x$. - Graph 3 is partially visible and mostly vertical, which does not match $y = e^x$. 6. Hence, the slope field corresponding to $y = e^x$ is Graph 2 (center). Final answer: Graph 2 corresponds to $y = e^x$.