1. **Stating the problem:** Balance the chemical equation for the reaction sodium hydroxide + barium sulphide → sodium sulphide + barium hydroxide.
2. **Write the unbalanced equation:**
$$\mathrm{NaOH + BaS \rightarrow Na_2S + Ba(OH)_2}$$
3. **Balance sodium (Na):**
On the left, 1 Na in NaOH; on the right, 2 Na in Na2S.
Multiply NaOH by 2:
$$2\mathrm{NaOH + BaS \rightarrow Na_2S + Ba(OH)_2}$$
4. **Balance barium (Ba):**
1 Ba on both sides, balanced.
5. **Balance sulfur (S):**
1 S on both sides, balanced.
6. **Balance oxygen (O) and hydrogen (H):**
Left: 2 O and 2 H from 2 NaOH.
Right: Ba(OH)2 has 2 OH groups → 2 O and 2 H.
Balanced.
7. **Final balanced equation:**
$$2\mathrm{NaOH + BaS \rightarrow Na_2S + Ba(OH)_2}$$
**Answer:** The balanced chemical equation is $$2\mathrm{NaOH + BaS \rightarrow Na_2S + Ba(OH)_2}$$.
Balance Naoh Bas 7F3A43
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