1. **State the problem:** We are given the chemical reaction equation: $$\text{Na}_3\text{PO}_4 + 3 \text{KOH} \rightarrow 3 \text{NaOH} + \text{K}_3\text{PO}_4$$ 2. **Explain the goal:** We want to verify if the equation is balanced, meaning the number of atoms of each element is the same on both sides. 3. **List elements involved:** - Sodium (Na) - Phosphorus (P) - Oxygen (O) - Potassium (K) - Hydrogen (H) 4. **Count atoms on reactants side:** - Na: $1 \times 3 = 3$ - P: $1 \times 1 = 1$ - O: $4 \times 1 + 1 \times 3 = 4 + 3 = 7$ - K: $3 \times 1 = 3$ - H: $3 \times 1 = 3$ 5. **Count atoms on products side:** - Na: $3 \times 1 = 3$ - P: $1 \times 1 = 1$ - O: $3 \times 1 + 4 \times 1 = 3 + 4 = 7$ - K: $1 \times 3 = 3$ - H: $3 \times 1 = 3$ 6. **Compare both sides:** - Na: 3 = 3 - P: 1 = 1 - O: 7 = 7 - K: 3 = 3 - H: 3 = 3 7. **Conclusion:** The equation is balanced as the number of atoms for each element is equal on both sides. **Final answer:** The chemical equation is balanced as written.