1. **Stating the problem:** Match the units in Column A with the correct units in Column B. 2. **Step 1: Understand the quantities and their units.** - Volume (V) is measured in liters (L) or milliliters (ml). - Pressure (P) is measured in atm, mm Hg, or kPa. - Temperature (T) is measured in Kelvin. - Quantity (n) is measured in moles. 3. **Step 2: Match each item:** - Volume (V) \rightarrow d. Liters (L), or milliliters (ml) - Pressure (P) \rightarrow c. atm, mm Hg, kPa - Temperature (T) \rightarrow b. Kelvin - Quantity (n) \rightarrow a. moles 1. **Stating the problem:** Predict what will happen to the volume of a gas under different conditions. 2. **Step 1: Recall gas laws:** - Boyle's Law: Volume and pressure are inversely proportional ($P \times V = \text{constant}$). - Charles's Law: Volume and temperature are directly proportional ($\frac{V}{T} = \text{constant}$). - Avogadro's Law: Volume and number of moles are directly proportional ($\frac{V}{n} = \text{constant}$). 3. **Step 2: Analyze each statement:** - As pressure increases, volume will decrease (Boyle's Law). - As temperature increases, volume will increase (Charles's Law). - As number of moles increases, volume will increase (Avogadro's Law). - As pressure decreases, volume will increase (Boyle's Law). - As temperature decreases, volume will decrease (Charles's Law). 1. **Stating the problem:** Calculate the volume of a bubble formed when a submarine breaks under high pressure. 2. **Given:** - Initial pressure $P_1 = 1.2$ atm - Initial volume $V_1 = 15,000$ L - Final pressure $P_2 = 250$ atm - Final volume $V_2 = ?$ 3. **Step 1: Use Boyle's Law for constant temperature:** $$P_1 \times V_1 = P_2 \times V_2$$ 4. **Step 2: Solve for $V_2$:** $$V_2 = \frac{P_1 \times V_1}{P_2}$$ 5. **Step 3: Substitute values:** $$V_2 = \frac{1.2 \times 15,000}{250}$$ 6. **Step 4: Calculate numerator:** $$1.2 \times 15,000 = 18,000$$ 7. **Step 5: Calculate volume:** $$V_2 = \frac{18,000}{250}$$ 8. **Step 6: Simplify fraction:** $$V_2 = 72$$ **Final answer:** The volume of the bubble will be $72$ liters.