1. **State the problem:** Find the molality of a solution prepared by dissolving 42.0 g of CaCl2 in 271 g of water. 2. **Formula for molality:** $$m = \frac{\text{moles of solute}}{\text{mass of solvent in kg}}$$ 3. **Calculate moles of CaCl2:** $$\text{moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{42.0}{110.98}$$ 4. **Calculate moles:** $$\text{moles} = 0.3785$$ 5. **Convert mass of solvent to kg:** $$271\ \text{g} = 0.271\ \text{kg}$$ 6. **Calculate molality:** $$m = \frac{0.3785}{0.271}$$ 7. **Simplify molality:** $$m = 1.396$$ **Final answer:** The molality of the solution is approximately $1.40$ mol/kg.