1. **State the problem:** We need to find how many grams of sodium chloride (NaCl) are required to prepare 450 mL of a 1 M (molar) NaCl solution. 2. **Recall the formula for molarity:** $$ M = \frac{\text{moles of solute}}{\text{liters of solution}} $$ 3. **Rearrange the formula to find moles of solute:** $$ \text{moles of solute} = M \times \text{liters of solution} $$ 4. **Convert volume from mL to L:** $$ 450\ \text{mL} = \frac{450}{1000} = 0.45\ \text{L} $$ 5. **Calculate moles of NaCl needed:** $$ \text{moles} = 1\ \text{mol/L} \times 0.45\ \text{L} = 0.45\ \text{mol} $$ 6. **Use molar mass to convert moles to grams:** $$ \text{mass} = \text{moles} \times \text{molar mass} = 0.45\ \text{mol} \times 58.44\ \frac{\text{g}}{\text{mol}} $$ 7. **Calculate the mass:** $$ \text{mass} = 26.298\ \text{g} $$ **Final answer:** You need approximately **26.3 grams** of sodium chloride to prepare 450 mL of a 1 M NaCl solution.