1. **State the problem:** We need to find how many grams of sodium chloride (NaCl) are required to prepare 450 mL of a 1 M NaCl solution. 2. **Recall the formula for molarity:** $$ M = \frac{\text{moles of solute}}{\text{liters of solution}} $$ 3. **Calculate moles of NaCl needed:** Given $M = 1$ and volume $V = 450$ mL $= 0.450$ L, $$ \text{moles} = M \times V = 1 \times 0.450 = 0.450 \text{ moles} $$ 4. **Calculate mass of NaCl:** Using molar mass $M_{NaCl} = 58.44$ g/mol, $$ \text{mass} = \text{moles} \times M_{NaCl} = 0.450 \times 58.44 = 26.298 \text{ grams} $$ 5. **Final answer:** You need approximately **26.3 grams** of sodium chloride to prepare 450 mL of a 1 M NaCl solution.