1. **State the problem:** Find the pH of a solution when the concentration of hydrogen ions $[H^+]$ is 0.0053 moles per liter.
2. **Recall the formula:** pH is defined as
$$\text{pH} = -\log [H^+]$$
where $[H^+]$ is the hydrogen ion concentration.
3. **Substitute the given value:**
$$\text{pH} = -\log(0.0053)$$
4. **Calculate the logarithm:**
First, express 0.0053 in scientific notation:
$$0.0053 = 5.3 \times 10^{-3}$$
5. **Use log properties:**
$$\log(5.3 \times 10^{-3}) = \log(5.3) + \log(10^{-3}) = \log(5.3) - 3$$
6. **Evaluate $\log(5.3)$:** approximately 0.7243
7. **Calculate pH:**
$$\text{pH} = - (0.7243 - 3) = -0.7243 + 3 = 2.2757$$
8. **Final answer:**
$$\boxed{\text{pH} \approx 2.28}$$
This means the solution is acidic since pH is less than 7.
Ph Calculation 6Ce31F
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