1. The problem is to find the pH given the formula involving logarithms and activity coefficients. 2. The pH is calculated using the formula $$\text{pH} = -\log[H^+]$$ where $[H^+]$ is the hydrogen ion concentration. 3. Given $\log \gamma = 0.3$, this represents the logarithm of the activity coefficient $\gamma$. 4. The activity coefficient affects the effective concentration of ions, so the corrected concentration is $[H^+] \times \gamma$. 5. Since $\log \gamma = 0.3$, then $\gamma = 10^{0.3} \approx 2$. 6. The pH given is 0.08, so the actual hydrogen ion concentration is $10^{-0.08} \approx 0.83$. 7. Correcting for activity, the effective concentration is $0.83 \times 2 = 1.66$. 8. The corrected pH is then $$-\log(1.66) \approx -0.22$$. 9. Therefore, the answer is that the corrected pH is approximately $-0.22$.