1. **State the problem:** We have 32 grams of a 25% antiseptic solution and want to dilute it to a 10% solution by adding distilled water. 2. **Formula used:** The amount of antiseptic remains the same before and after dilution. Use the formula: $$C_1V_1 = C_2V_2$$ where $C_1$ and $V_1$ are the initial concentration and volume, and $C_2$ and $V_2$ are the final concentration and volume. 3. **Identify known values:** - $C_1 = 25\% = 0.25$ - $V_1 = 32$ grams - $C_2 = 10\% = 0.10$ - $V_2 = V_1 + x$ where $x$ is the amount of distilled water added. 4. **Set up the equation:** $$0.25 \times 32 = 0.10 \times (32 + x)$$ 5. **Calculate:** $$8 = 0.10 \times (32 + x)$$ 6. **Divide both sides by 0.10:** $$\frac{8}{\cancel{0.10}} = \cancel{0.10} \times \frac{32 + x}{\cancel{0.10}}$$ $$80 = 32 + x$$ 7. **Solve for $x$:** $$x = 80 - 32 = 48$$ **Answer:** You should add 48 grams of distilled water to reduce the solution to 10%.