1. The problem is to evaluate the binomial coefficient $\binom{1}{2}$. 2. The binomial coefficient $\binom{n}{k}$ is defined as $\frac{n!}{k!(n-k)!}$ where $n!$ is the factorial of $n$. 3. Important rule: $\binom{n}{k} = 0$ if $k > n$ because you cannot choose more elements than are available. 4. Here, $n=1$ and $k=2$, and since $2 > 1$, $\binom{1}{2} = 0$. 5. Therefore, the final answer is: $$\binom{1}{2} = 0$$