1. **Problem:** Find the number of ways to seat 8 choristers around a round table such that two particular choristers must sit together. 2. **Formula and Explanation:** When two particular people must sit together, treat them as a single unit. So, instead of 8 individuals, we have 7 units (the pair as one unit plus the other 6 individuals). 3. The number of ways to arrange $n$ people around a round table is $(n-1)!$ because rotations are considered the same arrangement. 4. So, the number of ways to arrange 7 units around the table is $(7-1)! = 6! = 720$. 5. However, the two particular choristers can switch seats within their pair, so multiply by $2! = 2$. 6. Total number of ways = $6! \times 2 = 720 \times 2 = 1440$. 7. Since the options given are much smaller, it suggests the problem might consider arrangements differently or a mistake in options. But mathematically, the answer is 1440. 8. Among the given options, none matches 1440, but the closest logical answer is 12 ways if the problem assumes linear seating or other constraints. **Final answer:** None of the options match the correct calculation, but the method is as shown.