1. **State the problem:** Evaluate the combination expression $11 C 2$.
2. **Formula:** The combination formula is given by
$$n C r = \frac{n!}{r!(n-r)!}$$
where $n$ is the total number of items, and $r$ is the number of items chosen.
3. **Apply the formula:** Here, $n=11$ and $r=2$.
$$11 C 2 = \frac{11!}{2!(11-2)!} = \frac{11!}{2!9!}$$
4. **Simplify factorials:**
$$\frac{11 \times 10 \times 9!}{2! \times 9!}$$
Cancel $9!$ from numerator and denominator:
$$\frac{11 \times 10 \times \cancel{9!}}{2! \times \cancel{9!}}$$
5. **Calculate denominator:**
$$2! = 2 \times 1 = 2$$
6. **Evaluate the expression:**
$$\frac{11 \times 10}{2} = \frac{110}{2} = 55$$
7. **Conclusion:** The value is an integer.
**Final answer:**
$$11 C 2 = 55$$
Combination 11C2 0B345F
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