1. **Problem Statement:** Calculate the number of possible telephone numbers, dressing combinations, security alarm codes, and four-digit numbers based on given constraints.
2. **Telephone Numbers (Question 3):**
- i. Area codes: The first digit cannot be zero, so it can be any digit from 1 to 9 (9 options).
The next two digits can be any digit from 0 to 9 (10 options each).
Total area codes = $9 \times 10 \times 10 = 900$.
- ii. Local numbers: The first digit cannot be zero (9 options), and the remaining six digits can be any digit (10 options each).
Total local numbers = $9 \times 10^6 = 9,000,000$.
- iii. Total telephone numbers = area codes $\times$ local numbers = $900 \times 9,000,000 = 8,100,000,000$.
3. **Dressing Combinations (Question 4):**
- Number of suits = 4
- Number of ties = 3
- Number of shoes = 2
- Total ways = $4 \times 3 \times 2 = 24$.
4. **Security Alarm Codes (Question 5):**
- i. No digit repeated: For a 4-digit code, digits 0-9 (10 digits).
Number of codes = permutations of 10 digits taken 4 at a time = $P(10,4) = 10 \times 9 \times 8 \times 7 = 5040$.
- ii. Digits may repeat: Each digit can be any of 10 digits.
Number of codes = $10^4 = 10,000$.
5. **Four-digit numbers from digits 0,1,2,3,5,6 with no repetition (Question 6):**
- Digits available = 6
- First digit cannot be zero (to form a valid 4-digit number), so first digit options = 5 (1,2,3,5,6)
- Remaining 3 digits chosen from remaining 5 digits without repetition.
- Number of such numbers = $5 \times P(5,3) = 5 \times (5 \times 4 \times 3) = 5 \times 60 = 300$.
**Final answers:**
- Question 3: i. 900, ii. 9,000,000, iii. 8,100,000,000
- Question 4: 24
- Question 5: i. 5040, ii. 10,000
- Question 6: 300
Counting Problems Db9D51
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