1. **Problem:** A license plate must have 2 letters (not I or O) followed by 3 digits. The last digit cannot be zero. How many different plates can be made?
2. **Step 1: Determine the number of possible letters.**
- The English alphabet has 26 letters.
- Letters I and O are excluded, so available letters = $26 - 2 = 24$.
- Since 2 letters are needed, and repetition is allowed (not stated otherwise), number of ways to choose letters = $24 \times 24 = 24^2$.
3. **Step 2: Determine the number of possible digits.**
- Each digit can be from 0 to 9, so 10 digits total.
- The last digit cannot be zero, so last digit choices = 9 (digits 1 through 9).
- The first two digits can be any digit 0-9, so each has 10 choices.
- Number of ways to choose digits = $10 \times 10 \times 9 = 900$.
4. **Step 3: Calculate total number of license plates.**
- Total plates = (number of letter combinations) $\times$ (number of digit combinations)
- Total plates = $24^2 \times 900 = 576 \times 900 = 518400$.
**Final answer:** There are $518400$ different license plates possible.
License Plates 7A72Bc
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