1. **Stating the problem:** We need to find the number of different 5-digit combinations possible on a lock with 5 wheels labeled 0 to 9 under different conditions.
2. **Understanding the problem:** Each wheel can show digits from 0 to 9, so there are 10 possible digits per wheel.
3. **Case a: No digit is repeated.**
- For the first wheel, there are 10 choices.
- For the second wheel, since no repetition is allowed, there are 9 choices left.
- For the third wheel, 8 choices remain.
- For the fourth wheel, 7 choices remain.
- For the fifth wheel, 6 choices remain.
4. **Formula used:** The number of permutations of 10 digits taken 5 at a time is given by:
$$P(10,5) = 10 \times 9 \times 8 \times 7 \times 6$$
5. **Calculating:**
$$10 \times 9 = 90$$
$$90 \times 8 = 720$$
$$720 \times 7 = 5040$$
$$5040 \times 6 = 30240$$
6. **Answer:** The number of different 5-digit combinations possible if no digit is repeated is **30240**.
Lock Combinations 90B239
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