1. **Problem statement:** Calculate the number of different serial numbers possible on a dollar bill where the serial number consists of a letter, followed by eight digits, and then a letter.
2. **Given:**
- Number of letters in the alphabet = 26
- Number of vowels = 5 (not directly needed here)
- Number of consonants = 21 (not directly needed here)
- Digits = 0 to 9 (10 digits)
3. **Part 1: Letters and digits can be repeated.**
- The serial number format is: Letter (1) + Digit (8) + Letter (1)
- Number of choices for each letter = 26
- Number of choices for each digit = 10
4. **Formula:**
$$\text{Total possibilities} = (\text{letters}) \times (\text{digits})^8 \times (\text{letters})$$
5. **Calculation:**
$$26 \times 10^8 \times 26 = 26 \times 26 \times 10^8 = 676 \times 10^8 = 67600000000$$
6. **Part 2: Letters and digits cannot be repeated.**
- Letters: 26 letters, no repetition, so first letter has 26 choices, last letter has 25 choices (since one letter used already)
- Digits: 10 digits, no repetition, 8 digits chosen in order without repetition
- Number of ways to choose 8 digits without repetition from 10 digits in order is a permutation: $$P(10,8) = \frac{10!}{(10-8)!} = \frac{10!}{2!}$$
7. **Formula:**
$$\text{Total possibilities} = 26 \times P(10,8) \times 25 = 26 \times \frac{10!}{2!} \times 25$$
8. **Calculate permutations:**
$$10! = 3628800$$
$$2! = 2$$
$$P(10,8) = \frac{3628800}{2} = 1814400$$
9. **Final calculation:**
$$26 \times 1814400 \times 25 = 26 \times 25 \times 1814400$$
$$= 650 \times 1814400 = 1179360000$$
**Answer:**
- Part 1: $67600000000$
- Part 2: $1179360000$
Serial Numbers 847501
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