Subjects computer science

Savebuffer Size 223423

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1. **State the problem:** Calculate the size of the struct `SaveBuffer` given the sizes and counts of its components. 2. **Given data:** - `COURSE_STAGES_COUNT = 15` - `NUM_SAVE_FILES = 4` (from enum `SaveFileIndex`) 3. **Analyze each struct size:** - `SaveFile` contains: - `u8 capLevel` (1 byte) - `u8 capArea` (1 byte) - `Vec3s capPos` (3 shorts, each 2 bytes, total 6 bytes) - `u32 flags` (4 bytes) - `u8 courseStars[92]` (92 bytes) - `u8 courseCoinScores[COURSE_STAGES_COUNT]` (15 bytes) - `SaveBlockSignature signature` (size unknown, assume $S$ bytes) Calculate size of `SaveFile` without signature: $$1 + 1 + 6 + 4 + 92 + 15 = 119 \text{ bytes}$$ So, $$\text{Size of SaveFile} = 119 + S$$ 4. `MainMenuSaveData` contains: - `u32 coinScoreAges[NUM_SAVE_FILES]` (4 elements × 4 bytes = 16 bytes) - `u16 soundMode` (2 bytes) - `SaveBlockSignature signature` ($S$ bytes) Calculate size without signature: $$16 + 2 = 18 \text{ bytes}$$ So, $$\text{Size of MainMenuSaveData} = 18 + S$$ 5. `SaveBuffer` contains: - `files[NUM_SAVE_FILES]` (4 × size of `SaveFile`) - `menuData` (size of `MainMenuSaveData`) Calculate total size: $$4 \times (119 + S) + (18 + S) = 4 \times 119 + 4S + 18 + S = 476 + 5S + 18 = 494 + 5S$$ 6. **Final formula:** $$\boxed{\text{Size of SaveBuffer} = 494 + 5 \times S \text{ bytes}}$$ where $S$ is the size in bytes of `SaveBlockSignature`. Without knowing $S$, this is the most precise answer. If you provide the size of `SaveBlockSignature`, substitute it into the formula to get the exact size.