1. **State the problem:** We have a scatter plot showing the relationship between the number of hours worked ($x$) and the amount of money spent on entertainment ($y$) by 23 students. We want to find an approximate equation of the line of best fit and use it to predict the money spent for a student who works 10 hours. 2. **Formula for line of best fit:** The line of best fit is generally written as $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 3. **Estimate slope ($m$):** From the scatter plot, points roughly go from $(3,8)$ to $(19,26)$. Calculate slope: $$m = \frac{26 - 8}{19 - 3} = \frac{18}{16} = 1.125$$ 4. **Estimate y-intercept ($b$):** Use point-slope form with point $(3,8)$: $$8 = 1.125 \times 3 + b \implies b = 8 - 3.375 = 4.625$$ 5. **Write equation:** Rounded to nearest hundredth: $$y = 1.13x + 4.63$$ 6. **Prediction for $x=10$ hours:** Substitute $x=10$: $$y = 1.13 \times 10 + 4.63 = 11.3 + 4.63 = 15.93$$ **Final answers:** - (a) Equation of line of best fit: $$y = 1.13x + 4.63$$ - (b) Predicted money spent for 10 hours worked: $$15.93$$