1. **State the problem:** We have a scatter plot showing the relationship between time spent texting ($x$) and time spent exercising ($y$) for 24 students. We want to find an approximate equation of the line of best fit and use it to predict exercise time for a student who texts 4 hours. 2. **Formula for line of best fit:** The line of best fit is generally written as $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 3. **Estimate slope ($m$):** From the scatter plot, points roughly go from $(3.5, 5.0)$ down to $(9.3, 0.3)$ showing a negative trend. Calculate slope: $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0.3 - 5.0}{9.3 - 3.5} = \frac{-4.7}{5.8} \approx -0.81$$ 4. **Estimate intercept ($b$):** Use point $(3.5, 5.0)$ and slope $-0.81$: $$5.0 = -0.81 \times 3.5 + b$$ $$b = 5.0 + 0.81 \times 3.5 = 5.0 + 2.835 = 7.835 \approx 7.84$$ 5. **Equation of line of best fit:** $$y = -0.81x + 7.84$$ 6. **Prediction for $x=4$ hours texting:** $$y = -0.81 \times 4 + 7.84 = -3.24 + 7.84 = 4.60$$ 7. **Final answers:** (a) Approximate equation: $$y = -0.81x + 7.84$$ (b) Predicted exercise time for 4 hours texting: $$4.60$$ hours