1. The problem asks us to find between which two times the most pieces of sea glass were found and to estimate the number of pieces after 25 minutes. 2. We are given the number of pieces found at different times: | Time (minutes) | 10 | 20 | 30 | 40 | 50 | 60 | |----------------|----|----|----|----|----|----| | Pieces found | 4 | 10 | 20 | 26 | 29 | 35 | 3. To find between which two times the most pieces were found, calculate the difference in pieces between consecutive times: - Between 10 and 20 minutes: $10 - 4 = 6$ - Between 20 and 30 minutes: $20 - 10 = 10$ - Between 30 and 40 minutes: $26 - 20 = 6$ - Between 40 and 50 minutes: $29 - 26 = 3$ - Between 50 and 60 minutes: $35 - 29 = 6$ 4. The greatest increase is $10$ pieces between 20 and 30 minutes. 5. To estimate the number of pieces after 25 minutes, note that 25 minutes is halfway between 20 and 30 minutes. 6. Since the number of pieces at 20 minutes is 10 and at 30 minutes is 20, we can estimate the number at 25 minutes by averaging: $$\frac{10 + 20}{2} = 15$$ 7. Therefore, after 25 minutes, approximately 15 pieces of sea glass were found. Final answers: - The most pieces were found between 20 and 30 minutes. - Estimated pieces after 25 minutes: 15.