1. The problem is to complete the truth table for a logic circuit where inputs A and B go into an OR gate producing output C, which then goes into a NOT gate producing output Q. 2. The OR gate outputs 1 if either A or B is 1, otherwise 0. The NOT gate outputs the opposite of its input. 3. The formula for the OR gate is $$C = A \lor B$$ and for the NOT gate is $$Q = \neg C$$. 4. Calculate C for each input pair: - For A=0, B=0: $$C = 0 \lor 0 = 0$$ - For A=0, B=1: $$C = 0 \lor 1 = 1$$ - For A=1, B=0: $$C = 1 \lor 0 = 1$$ - For A=1, B=1: $$C = 1 \lor 1 = 1$$ 5. Calculate Q by negating C: - For C=0: $$Q = \neg 0 = 1$$ - For C=1: $$Q = \neg 1 = 0$$ 6. Complete truth table: | A | B | C | Q | |---|---|---|---| | 0 | 0 | 0 | 1 | | 0 | 1 | 1 | 0 | | 1 | 0 | 1 | 0 | | 1 | 1 | 1 | 0 |