1. **Problem Statement:** Determine whether the set of ordered pairs \(\{(b, a), (c, d), (d, a), (c, d), (a, d)\}\) is a function from \(W = \{a, b, c, d\}\) into \(W\).
2. **Definition of a Function:** A set of ordered pairs is a function if every element in the domain (here \(W\)) appears exactly once as the first element of an ordered pair. This means each input has exactly one output.
3. **Check the domain elements:** The domain is \(W = \{a, b, c, d\}\).
- Look at the first elements of the pairs: \(b, c, d, c, a\).
- Notice that \(c\) appears twice as the first element: \((c, d)\) and \((c, d)\) (repeated pair).
4. **Conclusion:** Since \(c\) appears more than once as the first element, the set is not a function (each input must have exactly one output).
**Final answer:** The set \(\{(b, a), (c, d), (d, a), (c, d), (a, d)\}\) is **not** a function from \(W\) into \(W\).
Function Check C1446E
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