1. The problem shows a mapping from Set A to Set B with elements and their images. 2. Set A = \{4, -2, 8\} and Set B = \{3, 6, 7, 9\}. 3. The mapping is given by: 4 \to 3, -2 \to 6, 8 \to 7. 4. This is a function from Set A to Set B because each element in Set A maps to exactly one element in Set B. 5. Note that 9 in Set B is not mapped to by any element in Set A. 6. The function can be written as $f(4) = 3$, $f(-2) = 6$, $f(8) = 7$. 7. This is an example of a function that is not onto (surjective) because not every element in Set B has a preimage in Set A. 8. It is also one-to-one (injective) because no two elements in Set A map to the same element in Set B. 9. Summary: The mapping is a function from Set A to Set B, injective but not surjective.