1. **State the problem:** We have a cost table with output (O), fixed cost (FC), average fixed cost (AFC), variable cost (VC), average variable cost (AVC), total cost (TC), and average total cost (ATC). Given some values, we need to find the missing values for output 6, 7, and 8. 2. **Recall formulas:** - Total Cost: $$TC = FC + VC$$ - Average Fixed Cost: $$AFC = \frac{FC}{O}$$ - Average Variable Cost: $$AVC = \frac{VC}{O}$$ - Average Total Cost: $$ATC = \frac{TC}{O} = AFC + AVC$$ 3. **Given values:** - For output 6: $$FC = 84$$, $$VC = 72$$ - For output 7: $$VC = 77$$ - For output 8: $$VC = 80$$ 4. **Calculate missing values for output 6:** - Total Cost: $$TC = 84 + 72 = 156$$ - Average Fixed Cost: $$AFC = \frac{84}{6} = 14$$ - Average Variable Cost: $$AVC = \frac{72}{6} = 12$$ - Average Total Cost: $$ATC = \frac{156}{6} = 26$$ or $$14 + 12 = 26$$ 5. **Calculate missing values for output 7:** - Fixed Cost remains the same: $$FC = 84$$ - Total Cost: $$TC = 84 + 77 = 161$$ - Average Fixed Cost: $$AFC = \frac{84}{7} = 12$$ - Average Variable Cost: $$AVC = \frac{77}{7} = 11$$ - Average Total Cost: $$ATC = \frac{161}{7} \approx 23$$ or $$12 + 11 = 23$$ 6. **Calculate missing values for output 8:** - Fixed Cost: $$FC = 84$$ - Total Cost: $$TC = 84 + 80 = 164$$ - Average Fixed Cost: $$AFC = \frac{84}{8} = 10.5$$ - Average Variable Cost: $$AVC = \frac{80}{8} = 10$$ - Average Total Cost: $$ATC = \frac{164}{8} = 20.5$$ or $$10.5 + 10 = 20.5$$ **Final answers:** | Output | FC | AFC | VC | AVC | TC | ATC | |--------|----|-----|----|-----|----|-----| | 6 | 84 | 14 | 72 | 12 |156 | 26 | | 7 | 84 | 12 | 77 | 11 |161 | 23 | | 8 | 84 |10.5 | 80 | 10 |164 |20.5 |