1. **State the problem:** Given a parallel circuit with total current $I_T = 0.65$ A, branch currents $I_2 = 220$ mA, $I_4 = 350$ mA, and voltage $V_2 = 4.5$ V, find the unknown currents $I_1$, $I_3$ and voltages $V_1$, $V_3$, and total voltage $V_T$. 2. **Relevant formulas and rules:** - In parallel circuits, voltage across each branch is the same: $$V_1 = V_2 = V_3 = V_T$$ - Total current is the sum of branch currents: $$I_T = I_1 + I_2 + I_3$$ - Current $I_4$ is given as 350 mA (likely the return current, equal to $I_T$ if no other branches). 3. **Convert units:** - $I_2 = 220$ mA $= 0.220$ A - $I_4 = 350$ mA $= 0.350$ A 4. **Calculate $I_1$:** Since $I_4$ is the return current and equals $I_1 + I_2$ (assuming $I_3$ is separate), $$I_4 = I_1 + I_2$$ $$I_1 = I_4 - I_2 = 0.350 - 0.220 = 0.130\text{ A}$$ 5. **Calculate $I_3$:** Using total current, $$I_T = I_1 + I_2 + I_3$$ $$I_3 = I_T - I_1 - I_2 = 0.65 - 0.130 - 0.220 = 0.300\text{ A}$$ 6. **Voltages in parallel:** $$V_1 = V_2 = V_3 = V_T = 4.5\text{ V}$$ **Final answers:** - $I_1 = 0.130$ A - $I_3 = 0.300$ A - $V_1 = 4.5$ V - $V_3 = 4.5$ V - $V_T = 4.5$ V