1. **Problem Statement:** Calculate the impedance of the inductor alone with inductive reactance $X_L=16\ \Omega$. 2. **Formula and Rules:** - The impedance of a pure inductor is purely imaginary and given by: $$Z_L = jX_L$$ where $j$ is the imaginary unit and $X_L$ is the inductive reactance. 3. **Calculate the impedance of the inductor:** Given $X_L = 16\ \Omega$, the impedance is: $$Z_L = j16\ \Omega$$ 4. **Interpretation:** - This means the inductor's impedance has zero real part (no resistance), and the entire impedance is reactive. - The phase angle of the inductor's impedance is $90^\circ$ because it is purely imaginary and positive. **Final answer:** - Impedance of the inductor: $Z_L = j16\ \Omega$ - Magnitude: $|Z_L| = 16\ \Omega$ - Phase angle: $90^\circ$