1. **Problem Statement:** Find the output voltage $V_0$ of the given op-amp circuit with resistors and a 5 V input. 2. **Identify the configuration:** This is an op-amp with resistors arranged to form a difference amplifier. 3. **Formula for difference amplifier output voltage:** $$V_0 = \left(\frac{R_f}{R_{in}}\right)(V_2 - V_1)$$ where $R_f$ is the feedback resistor, $R_{in}$ is the input resistor, $V_1$ is voltage at the inverting input, and $V_2$ is voltage at the non-inverting input. 4. **Assign resistor values:** - $R_f = 1\text{k}\Omega$ - $R_{in} = 1\text{k}\Omega$ - The resistor to non-inverting input is $4\text{k}\Omega$ and the resistor from non-inverting input to ground is $4\text{k}\Omega$. 5. **Calculate $V_2$ (non-inverting input voltage):** Using voltage divider: $$V_2 = 5 \times \frac{4}{4 + 4} = 5 \times \frac{4}{8} = 2.5\text{ V}$$ 6. **Calculate $V_1$ (inverting input voltage):** Since the op-amp input draws no current, $V_1$ is at virtual ground potential, so $V_1 = 0$ V. 7. **Calculate output voltage $V_0$:** $$V_0 = \left(\frac{1\text{k}\Omega}{1\text{k}\Omega}\right)(2.5 - 0) = 1 \times 2.5 = 2.5\text{ V}$$ 8. **Check options:** None of the options match 2.5 V exactly, so the answer is (e) None of the above. **Final answer:** $V_0 = 2.5$ V, so option (e) None of the above.