1. **Problem Statement:** Determine the collector-emitter voltage $V_{CE}$ and the base current $I_B$ for a transistor in common emitter configuration with given parameters: - Collector supply voltage $V_{CC} = 8V$ - Voltage drop across collector resistor $V_{RC} = 0.5V$ - Collector resistor $R_C = 800\ \Omega$ - Current gain $\alpha = 0.96$ 2. **Formulas and Important Rules:** - Collector current $I_C = \frac{V_{RC}}{R_C}$ - Emitter current $I_E = \frac{I_C}{\alpha}$ - Base current $I_B = I_E - I_C$ - Collector-emitter voltage $V_{CE} = V_{CC} - V_{RC}$ 3. **Calculations:** - Calculate collector current: $$I_C = \frac{0.5}{800} = 0.000625\ A = 0.625\ mA$$ - Calculate emitter current: $$I_E = \frac{I_C}{\alpha} = \frac{0.000625}{0.96} \approx 0.000651\ A = 0.651\ mA$$ - Calculate base current: $$I_B = I_E - I_C = 0.000651 - 0.000625 = 0.000026\ A = 26\ \mu A$$ - Calculate collector-emitter voltage: $$V_{CE} = V_{CC} - V_{RC} = 8 - 0.5 = 7.5\ V$$ **Final answers:** - Collector-emitter voltage $V_{CE} = 7.5\ V$ - Base current $I_B = 26\ \mu A$