1. **Problem Statement:** A transistor in common emitter configuration has collector supply voltage $V_{CC} = 8$ V, voltage drop across collector resistor $V_{RC} = 0.5$ V, and resistor $R_C = 800\ \Omega$. Given current gain $\alpha = 0.96$, find: (i) Collector-emitter voltage $V_{CE}$ (ii) Base current $I_B$ 2. **Formulas and Rules:** - Collector current $I_C = \frac{V_{RC}}{R_C}$ - Emitter current $I_E = \frac{I_C}{\alpha}$ - Base current $I_B = I_E - I_C = I_C \left(\frac{1}{\alpha} - 1\right)$ - Collector-emitter voltage $V_{CE} = V_{CC} - V_{RC} - V_E$ (assuming emitter voltage $V_E$ is 0 V here) 3. **Calculate Collector Current $I_C$:** $$I_C = \frac{0.5}{800} = 0.000625\ A = 0.625\ mA$$ 4. **Calculate Emitter Current $I_E$:** $$I_E = \frac{I_C}{\alpha} = \frac{0.000625}{0.96} \approx 0.000651\ A = 0.651\ mA$$ 5. **Calculate Base Current $I_B$:** $$I_B = I_E - I_C = 0.000651 - 0.000625 = 0.000026\ A = 26\ \mu A$$ 6. **Calculate Collector-Emitter Voltage $V_{CE}$:** Since emitter is grounded, $V_E = 0$, so $$V_{CE} = V_{CC} - V_{RC} = 8 - 0.5 = 7.5\ V$$ **Final answers:** (i) $V_{CE} = 7.5$ V (ii) $I_B = 26$ $\mu$A