1. **State the problem:**
We are given two electric charges Q₁ and Q₂ located at points with Cartesian coordinates (1, 2, 3) and (−1, −3, 3) respectively. We need to determine:
(I) The distance vector \(\overrightarrow{Q_1 Q_2}\)
(II) The distance between Q₁ and Q₂.
2. **Formula and rules:**
- The distance vector from point \(Q_1(x_1,y_1,z_1)\) to \(Q_2(x_2,y_2,z_2)\) is given by:
$$\overrightarrow{Q_1 Q_2} = (x_2 - x_1, y_2 - y_1, z_2 - z_1)$$
- The distance between two points in 3D space is the magnitude of the distance vector:
$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}$$
3. **Calculate the distance vector:**
Given \(Q_1 = (1, 2, 3)\) and \(Q_2 = (-1, -3, 3)\),
$$\overrightarrow{Q_1 Q_2} = (-1 - 1, -3 - 2, 3 - 3) = (-2, -5, 0)$$
4. **Calculate the distance:**
$$d = \sqrt{(-2)^2 + (-5)^2 + 0^2} = \sqrt{4 + 25 + 0} = \sqrt{29}$$
5. **Final answers:**
(I) Distance vector \(\overrightarrow{Q_1 Q_2} = (-2, -5, 0)\)
(II) Distance between Q₁ and Q₂ is \(\sqrt{29}\) units.
Distance Vector F03Dbb
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