1. **Problem statement:** Calculate the amount in a savings account after a certain number of years with compound interest. 2. **Formula used:** The compound interest formula is $$A = P \times (1 + r)^n$$ where: - $A$ is the amount after $n$ years, - $P$ is the principal (initial amount), - $r$ is the annual interest rate (as a decimal), - $n$ is the number of years. 3. **Given data:** - Start amount $P = 2500$ - After 1 year amount $A_1 = 2630$ - Interest rate $r$ is unknown but can be found from the data. 4. **Find the interest rate $r$:** $$2630 = 2500 \times (1 + r)^1$$ Divide both sides by 2500: $$\frac{2630}{2500} = \cancel{\frac{2500}{2500}} \times (1 + r)$$ $$1.052 = 1 + r$$ Subtract 1 from both sides: $$r = 1.052 - 1 = 0.052$$ So the interest rate is 5.2% per year. 5. **Calculate amount after 10 years:** Using the formula: $$A = 2500 \times (1 + 0.052)^{10}$$ Calculate the power: $$A = 2500 \times (1.052)^{10}$$ Using a calculator: $$1.052^{10} \approx 1.677$$ Multiply: $$A = 2500 \times 1.677 = 4192.5$$ 6. **Final answer:** After 10 years, the amount in the savings account will be approximately **4192.50**.