1. **State the problem:** Hiran invests 20000 rupees at an interest rate of 1.5% per year compounded annually for 3 years. We need to find the total amount in the account after 3 years. 2. **Formula used:** The compound interest formula is $$A = P \left(1 + \frac{r}{100}\right)^n$$ where: - $A$ is the amount after $n$ years, - $P$ is the principal amount (initial investment), - $r$ is the annual interest rate (in percent), - $n$ is the number of years. 3. **Substitute the values:** $$P = 20000, \quad r = 1.5, \quad n = 3$$ So, $$A = 20000 \left(1 + \frac{1.5}{100}\right)^3 = 20000 \left(1 + 0.015\right)^3 = 20000 \times 1.015^3$$ 4. **Calculate the power:** $$1.015^3 = 1.015 \times 1.015 \times 1.015 = 1.04568$$ (rounded to 5 decimal places) 5. **Calculate the amount:** $$A = 20000 \times 1.04568 = 20913.6$$ 6. **Round to the nearest rupee:** $$\boxed{20914}$$ So, the total amount in the account after 3 years is 20914 rupees.