1. **State the problem:** Calculate the amount in an account after 2 years if 7500 is invested at an annual interest rate of 8% compounded annually. 2. **Formula used:** The compound interest formula is: $$A = P\left(1 + \frac{r}{N}\right)^{Nt}$$ where: - $A$ is the amount after time $t$, - $P$ is the principal (initial investment), - $r$ is the annual interest rate (decimal), - $N$ is the number of times interest is compounded per year, - $t$ is the number of years. 3. **Identify values:** - $P = 7500$ - $r = 0.08$ (8% as decimal) - $N = 1$ (compounded annually) - $t = 2$ 4. **Substitute values into the formula:** $$A = 7500\left(1 + \frac{0.08}{1}\right)^{1 \times 2} = 7500\left(1 + 0.08\right)^2 = 7500(1.08)^2$$ 5. **Calculate the power:** $$1.08^2 = 1.08 \times 1.08 = 1.1664$$ 6. **Calculate the amount:** $$A = 7500 \times 1.1664 = 8748$$ 7. **Interpretation:** After 2 years, the account will have 8748. 8. **Note on the annotation $P + 1800$:** The interest earned is $8748 - 7500 = 1248$, not 1800, so the annotation might be incorrect or from a different context. **Final answer:** $$\boxed{8748}$$