1. **State the problem:** We want to find the amount of money in an account after 29 years if 7800 dollars is deposited at an annual interest rate of 6.5%. 2. **Formula used:** For compound interest, the formula is $$A = P \left(1 + \frac{r}{n}\right)^{nt}$$ where: - $A$ is the amount after time $t$, - $P$ is the principal (initial amount), - $r$ is the annual interest rate (decimal), - $n$ is the number of times interest is compounded per year, - $t$ is the number of years. 3. **Assumption:** Since the problem does not specify compounding frequency, we assume interest is compounded once per year ($n=1$). 4. **Plug in values:** $$P = 7800, \quad r = 0.065, \quad n = 1, \quad t = 29$$ 5. **Calculate:** $$A = 7800 \left(1 + \frac{0.065}{1}\right)^{1 \times 29} = 7800 (1.065)^{29}$$ 6. **Intermediate step:** Calculate $(1.065)^{29}$: $$ (1.065)^{29} \approx 5.349 $$ 7. **Final amount:** $$ A = 7800 \times 5.349 = 41722.2 $$ 8. **Answer:** The amount in the account after 29 years will be approximately **41722.20** dollars.