1. **State the problem:** We want to find the present investment amount $P$ that will grow to $3000$ in 3 years at an interest rate of 5% per year compounded continuously.
2. **Formula used:** For continuous compounding, the amount $A$ after time $t$ is given by:
$$A = Pe^{rt}$$
where:
- $P$ is the principal (initial investment),
- $r$ is the annual interest rate (as a decimal),
- $t$ is the time in years,
- $e$ is Euler's number (approximately 2.71828).
3. **Rearrange the formula to solve for $P$:**
$$P = \frac{A}{e^{rt}}$$
4. **Substitute the known values:**
$$A = 3000, \quad r = 0.05, \quad t = 3$$
So,
$$P = \frac{3000}{e^{0.05 \times 3}} = \frac{3000}{e^{0.15}}$$
5. **Calculate the denominator:**
$$e^{0.15} \approx 1.16183424$$
6. **Calculate $P$:**
$$P = \frac{3000}{1.16183424} \approx 2581.98$$
7. **Final answer:**
You should invest approximately **2581.98** now to have 3000 in 3 years with continuous compounding at 5% interest.
Continuous Compounding Df67E7
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